Question

How should I approach e^(2x) - e^x - 6 = 0 to solve for x?

Answer 1

let u=e^x
u^2-u-6=0
(u-3)(u+2)=0
u=3 => e^x=3 =>x=ln3
u=-2 cant have log of a negative
x=ln3 is only solution

Answer 2

thank you.