Question

A circle has the equation 48x squared + 48y squared-32x-42y-13=0.
Find the center, radius and intercepts of the circle.

Answer 1

The center is 1/3 and 1/4
I've got that part.

Answer 2

\[Given Equation: 48x ^{2}+48y ^{2}-32x-42y-13=0\]

-> divide by 48
\[x ^{2}+y ^{2}-2/3x-7/8y-13/48=0\]
->
\[(x ^{2}-2/3x+1/9) +(y ^{2}-7/8y+49/256) -1/9-49/256-13/48=0\]
->
\[(x-1/3)^{2}+(y-7/16)^{2}=1/9+49/256+13/48\]

You will get centre, radius and intercepts.

Answer 3

thanks