Question

Help me please!

In a triangle ABC, Angle B is 3 times Angle A. Angle C is 19 degrees less than 6 times Angle A. Find the size of the angles.

Answer 1

B= 3 A
C = 6A - 19
A + B + C = 180
A + 3A + 6A - 19 = 180
10A = 180 + 19
10 A = 199 => A = 19.9 degree
B = 3A = 19.9 x 3
C = 6A - 19 = 6 (19.9) - 19

Answer 2

\[A + B + C = 180\]
\[A + 3*A + 6*A - 19 = 180\]
\[10A = 199\]
A = 19.9
B = 59.7
C = 100.4

Answer 3

Thank you!