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The surface areas of two similar solids are 289 ft^2 and 900 ft^2 . the volume of the larger solid id 1755ft^3.what is the volume of the smaller solid?
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ahh here we go again. take the original ratio \[\frac{289}{900}\] take the square root to get \[\frac{17}{30}\] and then cube it to get your answer
the ratio of the volumes is \[\frac{4913}{27000}\] so multiply by 1755m by that to get smaller volume
so it would be 319 right
i didn't do it but i will
yeah 319 and a little
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okay thanks
yw hope method is clear
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