Question

Given the equation x^2-6x+y^2-8y-299=0 complete the square for both x and y. What is the result?

Answer 1

\[(x-3)^2+(y-4)^2=299+3^2+4^2\]

Answer 2

i get
\[(x-3)^2+(y-4)^2=324

Answer 3

\[(x-3)^2+(y-4)^2=324\]

Answer 4

alright thanks mate

Answer 5

gives you a circle with center at (3,4) and radius of 18 (since 18^2=324)

Answer 6

yw