Question

Given the equation x^2-7x=0 what constant must be added to both sides so the left side is the square of a binomial?

Answer 1

(7/2)^2

Answer 2

LHS becomes

(x) ^2 - 2(x)(7/2) + (7/2)^2 = (x - 7/2)^2

Answer 3

complete the square by adding the square of b/2 to both sides