Question

evaluate the integral: ( x^3 - 7 - 3/x^4) dx

Answer 1

x^4/4 - 7x +1/x^(-3) +c

Answer 2

i dont get how the part is written after the +1

Answer 3

it should be : \[1/x ^{3}\]

Answer 4

\[=x ^{4}/4 -7x +1/x^3 +const\]

Answer 5

ok so x^3 is in the denominator right?

Answer 6

right