Question

ANSWERS GET MEDALS
Find the distance from the center of the circle
x^2+y^2-8x+6y=1
The point A(-5,-6)

Answer 1

x^2-8x+y^2+6y=1
x^2-8x+4^2+y^2+6y+3^2=1+4^2+3^2
(x-4)^2+(y+3)^2=25
center of circle is (4,-3)

Answer 2

centre is 4, -3 - then use pythagoras to find reqd distance

Answer 3

d=sqrt{(-5-4)^2+(-6-(-3))^2}
d=sqrt{81+9}
d=sqrt{90}

Answer 4

3sqrt10?