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The perimeter of a rectangle is 124 inches. The length exceeds the width by 10 inches. what is the length in inches? what is the width in inches?
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26 and 36
let widht be x let lenght b (x+10) finally 2(l+ b) = 124
perimeter of a rectangle is 2x + 2y = 124 y = w + 10 substitute 2x + 2 (x + 10) = 124 solve for x. Use x to back substitute for y 2x + 2x + 20 = 124 4x = 104 x = 26 y = 36 check 26*36 = 124 i hope
2 [x+10(x)] 2 [x^2 + 10x] = 124
a+b = 62 and a-b = 10 => a=36, b = 26
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so length is 36 and width is 26?
yes!
thank you all
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