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OpenStudy (anonymous):
square root of 72x^3y^4z^9
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OpenStudy (saifoo.khan):
6root2 x^3/2 root3y^2 2z^3
OpenStudy (anonymous):
I understand how you got 6root2x^3/2 but I don't understand root 3y^2 2z^3
OpenStudy (saifoo.khan):
come here
jhonyy9 (jhonyy9):
(72x*3y*4z*9)*(1/2) =(36)(2)x*2(x)(y*2)*2(z*4)*2(z) =6xy*(2)z*(4)radical(2xz)
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