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Evaluate: 20 / 2y - y, for y = 5
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20/2(5) -5 = 20/10 - 5 = 10-5 = 5
\begin{align} 20/2(5) - (5)&=20/10 - 5\\ &=10-5\\ &=5 \end{align} maybe
Do I do anything with that stupid y?
which y is the stupid one? :)
Haha, the 2y. Or is this problem saying that the 2y is actually a hidden 5, and it is then subtracting another 5?
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the y itself is just standing in line holding someone place tell they get back; it just so happens that its holding the 5s place :)
That is very clever! :) Thanks again, you're awesome!
yep :)
Hello guys, can you help me with an algebra problem? -3y^3-5y-6(y+2y^3)
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