Question

solve the following system
2x+3x-z=1
3x+y+2z=12
x+2y-3z=-5

a) (3, 1, 2)
b) (-3, 1 , 2)
c) (3 , -1 , 2)
d) (3 , 1 , -2)

Answer 1

Are you sure you posted this correctly. You should double-check...

Answer 2

2x+3y-z=1
3x+y+2z=12
x+2y-3z=-5

Answer 3

I'm almost certain somebody will solve this for you...

Answer 4

i really don't know who can help me with this ..

Answer 5

The only reason why I don't want to help you is all you're interested in is the answer

Answer 6

oh come on man, please ..

Answer 7

Please give you the answer???

Answer 8

or solve it, it's okay just please please help me, i need the answer .

Answer 9

x=3, y=-1, z=2

Answer 10

I'm not really a big fan of giving just the answer only...

Answer 11

since they give you the points, its easier to see which one fits rather than trying to work out the answer

Answer 12

it aint a or d

Answer 13

looks like c fits all of them

Answer 14

when given multiple choice, the answer is already there, just see what fits :)

Answer 15

(2x + 3y -z = 1)2 ~ 4x + 6y -2z = 2

4x + 6y -2z = 2
3x+y+2z=12 ~ 7x + 7y = 14

(3x+y+2z=12)3
(x+2y-3z=-5)2 ~ 11x + 7y = 26

7x + 7y = 14
-(11x + 7y = 26) ~ -4x = -12 - - -> x=3

11(3) + 7y = 26
33 + 7y = 26 - - -> y=-1

2x + 3y - z = 1
2(3) + 3(-1) -z = 1
6 + (-3) -z = 1
3-z = 1
-z = 1-3
-z = -2 - - -> z=2

Answer 16

ITS
letter c