Question

find the equation of a circle whose centre is (-3,-2) radius is 4

Answer 1

should be \[\left( x--3 \right)^{2}+\left( y--2 \right)^{2}=4^{2}\]
if i am not mistaken you should get \[x ^{2}+y ^{2}+6x+4y=3\]

Answer 2

\[x^2-6x+y^2+4y=3\]
check the signs
and thanx