Question

help me pls,,,
marvin invested P6000 more at 5% than he invested at 8%. his total income was P2420 . how much did he invested at each rate?

Answer 1

I think he invested 16308 at 8% and (16308+6000) at 5%.
16308 * 8% + (16308+6000) * 5% = 2420

Answer 2

Might be a redundant question but should the amount of time be taken into consideration?

Answer 3

what's the solution?

Answer 4

hello

Answer 5

the question does not make sense

Answer 6

what is P1600 ?

Answer 7

P stands for pounds?

Answer 8

with a name like kyragayle, you must be a british

Answer 9

no im not

Answer 10

what the heck is P6000? is that dollars? P is what?

Answer 11

marvin is a flutter up

Answer 12

do we need that P ?

Answer 13

i can answer this if we ignore the P , did you mean to write $ instead of P

Answer 14

let x = amount invested at 8%
y = amount invested at 5%
it says that y = 6000 + x
because the amount invested at 5% is 6000 more than the amount invested at 8%.
so we have
.05 ( 6000 + x ) + .08 x = 2420

Answer 15

i get x = 16307.69

Answer 16

i think she was using I=Prt, or Interest = Principle x rate x time, thus the total amount of interest = the original amount x rate of interest (usually in decimals) x the amount of time (months, years, etc). might be where the P came from.

Answer 17

oh, then i answered a different question?

Answer 18

nah i think you got it right, just sayin she was noting it was principle

Answer 19

wait, does it change the answers? let me see

Answer 20

wait, P6000 means P = 6000, i think

Answer 21

the principal is 6000 , so you dont need your whole I = Prt thing

Answer 22

because youre given P, r is also given, and t is probably over a year since its not given

Answer 23

zhill, the time actually gets factored out

Answer 24

i know, just pointing out the SHE may have been clarifying for the rest of the world.

Answer 25

p is peso

Answer 26

actually the time does not get factored out, this problem is ill defined

Answer 27

Let x = amount of Peso invested at 8%
then x+6000 = amount of Pesos invested at 5%
.08x = amount of annual income from 8% investment
.05(x+6000) = amount of annual income from 5% investment.
.08x +.05(x+6000)=total annual income from total investments
.08x+.05(x+6000)=2420 (Pesos) Solve this for x
.08x + .05x + 300=2420
.13x=2420-300=2120 or .13x=2120
x=16307.69 peso at 8%
22307.69 pesos at 5%