Question

what is the inverse of y=-4x^2-2

Answer 1

First solve for x. \[x=\sqrt{(y+2)/-4}\] Now interchange the roles of x and y to get your inverse function:\[y=\sqrt{(-x-2)/4}\]remembering that we can't take the square root of a negative number the domain of this function is: \[(-x-2)/4\ge0\]So, \[-x \ge2\]Or,\[x \le-2\]

Answer 2

inverse operation?