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An arch has the shape of the parabola y = 36 − x2. A rectangle is fit under the arch by selecting a point (x, y) on the parabola. (a) Express the area A of the rectangle in terms of x. (b) If x = 1, the rectangle has base 2 and height 35. Find the base of a second rectangle that has the same area.
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thats fairly easy too
not the best picture , but good enough
assuming its symmetric about y axis , which it most likely is the area is (2x) y , ie base times height
A=2xy but y= 36-x^2 so A=2x ( 36-x^2)
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so base is 2x and all theyare asking for second part is to solve A= 70
72x -2x^3 =70
this is a cubic, requires polynomial division etc like all the others you have been doing
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