Question

kindly help me:
-4+3(x^2-2[y-3(x^2-y)]+4}

Answer 1

=21x^2-24y+8
Hope i haven't forgotten anything...oO

Answer 2

-4+3{x^2-2[y-3(x^2-y)]+4}
=-4+3*x^2-3*2[y-3(x^2-y)]+3*4
=-4+3x^2-6[y-3(x^2-y)]+12
=-4+3x^2-6*y+18(x^2-y)+12
=-4+3x^2-6y+18x^2-18y+12
=21x^2-24y+8