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find the locus of a point p(x,y) which moves so that its distance from the point (1,0) is half its distance from the line x=-1 whats my y point the second coordinate
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\[(x-1)^2 + (y)^2 = (x+1)^2/4(1)\]
whats my y point? for d2?
u dont have a y in the lines eqn so skip it
y is arbritrary
?
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no..uve got a y on the left side havent u?
so my final answer is x^2-2x+1+2y^2=0
yes
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