Question

a triangular lot has a perimeter of 1900ft one side is 200ft longer than the shortest side while the third side is 500ft longer than the shortest side find the lengths of all three sides

Answer 1

let shortest side be = m
then other side is = m+200
third side is = m+500

ATQ m + m+ 200 + m + 500 = 1900
3m + 700 = 1900

Answer 2

assign variables shortest to largest a -> b - > c
a+b+c=1900
a+200=b
a+500=c

Answer 3

plug n chug

Answer 4

m = (1900-700)/3 = 1200/3 = 400

so shortest side is = m = 400m
second side = m+200 = 600m
third side = m+500 = 900m

Answer 5

thanks guys

Answer 6

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