Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

|[x+2]| when x=-2,1 [|x+2|] when x=-2,1 plz help :(

OpenStudy (anonymous):

x=-2.1 is it true?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

x=2 and x=1 ya?

OpenStudy (anonymous):

i mean one time x=2 and the other time is x=1

OpenStudy (anonymous):

x=-2

OpenStudy (anonymous):

x=-2

OpenStudy (anonymous):

got it:)

OpenStudy (anonymous):

x=-2 so x+2=0 and [x+2] = |[x+2]| = 0

OpenStudy (anonymous):

okey

OpenStudy (anonymous):

x=1; x+2=3 and [x+2]=|[x+2]|=3 is it ok?

OpenStudy (anonymous):

yeah i did the same

OpenStudy (anonymous):

is there any problem else?

OpenStudy (anonymous):

how about the second ?

OpenStudy (anonymous):

[|x+2|]

OpenStudy (anonymous):

oh. x=-2 so |x+2|=0 and [|x+2|] =0

OpenStudy (anonymous):

x=1; |x+2| =3 and [|x+2|]=3 ok?

OpenStudy (anonymous):

thank`s alot hamed

OpenStudy (anonymous):

you are welcome:)

OpenStudy (anonymous):

after long time when i want to solved math , it `s come funny to me

OpenStudy (anonymous):

no. u only should more practice:)

OpenStudy (anonymous):

i solved it

OpenStudy (anonymous):

just in doubt

OpenStudy (anonymous):

it's natural for u at first. don't worry:)

OpenStudy (anonymous):

it seams you are iranian , aren`t u?

OpenStudy (anonymous):

yes:)

OpenStudy (anonymous):

good

OpenStudy (anonymous):

glad to meet u dear Pasha:)

OpenStudy (anonymous):

cya later

OpenStudy (anonymous):

same here,hamed

OpenStudy (anonymous):

hope 2

OpenStudy (anonymous):

khodahafez

OpenStudy (anonymous):

khoda negahdar:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!