Question

Fully expand the following logarithm and simplify if possible. Log(2) 8xy

Answer 1

log8+log x + log y (all to the base 2)

Answer 2

\[\log_{2}8xy =\log_{2}8 +\log_{2}x + \log_{2}y =\log_{2}2^3 + \log_{2}x +\log_{2}y = 3 + \log_{2}x + \log_{2}y \]

Answer 3

yeah. his answer is better.