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Mathematics 19 Online
OpenStudy (anonymous):

[x²-(3x+2)]³ =????? :)

OpenStudy (anonymous):

\[ = x ^{3} - 3x^4(3x+2) + 3x^2(3x + 2)^2 - (3x + 2)^3\]

OpenStudy (anonymous):

how did you do it? :D

OpenStudy (anonymous):

Use the ``difference of cubes`` for factor the expression. \[(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3\] ;)

OpenStudy (anonymous):

ohh, thank you :)

OpenStudy (anonymous):

U are welcome, sweety

OpenStudy (anonymous):

n tnx 4 a given medal

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