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log x^2-2x-3/x^2-4-log x^2+7x+6/x+2 epress as single log
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x^2 -2x -3 = (x-3)(x+1) x^2-4 =(x-2)(x+2) x^2 +7x +6 = (x+6)(x+1)
.
\[\log (A) -\log(B) = \log \frac{A}{B}\]
\[\frac{A}{B} = \frac{ (x-3)(x+1)}{(x+2)(x-2)} \times \frac{x+2}{(x+6)(x+1)}\]
\[\frac{A}{B} = \frac{x-3}{(x-2)(x+6)}\]
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Thanks could YOU help me get some more
\[\log \frac{(x-3)}{(x-2)(x+6)}\]
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