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Mathematics 20 Online
OpenStudy (anonymous):

log(64)x=2/3 solve

OpenStudy (dumbcow):

\[\log_{b}x = y \rightarrow x = b^{y} \]

OpenStudy (dumbcow):

x = 64^(2/3) just move the base over and push the number on right hand side up as exponent

OpenStudy (dumbcow):

every log has a base, its the number you put in parenthesis

OpenStudy (dumbcow):

you need to learn how to go from log form to exponential form and vica versa answer is 64^(2/3), cubed root of 64 squared use a calculator

OpenStudy (anonymous):

1365?

OpenStudy (dumbcow):

type it in just like i have it...64^(2/3)

OpenStudy (dumbcow):

or recognize cubed root of 64 is 4 4 squared is 16

OpenStudy (anonymous):

o ok sweet thanks mate

OpenStudy (dumbcow):

np :)

OpenStudy (anonymous):

\[\log_{a}y=x \] \[y=a ^{x}\] log(64)x=2/3 --->x = 64^(2/3) x=(16)

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