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log(64)x=2/3 solve
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\[\log_{b}x = y \rightarrow x = b^{y} \]
x = 64^(2/3) just move the base over and push the number on right hand side up as exponent
every log has a base, its the number you put in parenthesis
you need to learn how to go from log form to exponential form and vica versa answer is 64^(2/3), cubed root of 64 squared use a calculator
1365?
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type it in just like i have it...64^(2/3)
or recognize cubed root of 64 is 4 4 squared is 16
o ok sweet thanks mate
np :)
\[\log_{a}y=x \] \[y=a ^{x}\] log(64)x=2/3 --->x = 64^(2/3) x=(16)
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