Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

r-4/7=-1

OpenStudy (anonymous):

hey hero im glad your here

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Is (r-4) in the numerator?

OpenStudy (anonymous):

(r-4)/7 = -1 ?

OpenStudy (anonymous):

-3/7

OpenStudy (anonymous):

i will go now sorry i will back honey

OpenStudy (anonymous):

k

OpenStudy (anonymous):

It could be -7/4

OpenStudy (anonymous):

or 7/4

OpenStudy (anonymous):

roseanne you have to use parentheses

OpenStudy (anonymous):

look r - (4/7) = -1

OpenStudy (anonymous):

wait...

OpenStudy (anonymous):

lol youve made your mind up its -4/7 thank you I dont know what idf do w/o u

OpenStudy (anonymous):

wait....it's -3/7

OpenStudy (anonymous):

hero go ahead what????

OpenStudy (anonymous):

Okay....wait... http://www.twiddla.com/

OpenStudy (anonymous):

go there...

OpenStudy (angela210793):

r - (4/7) = -1 r=-7/7+4/7 r=-3/7

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

he was right!!!! thanx girl

OpenStudy (anonymous):

But go here real quick... http://www.twiddla.com/563490

OpenStudy (anonymous):

You wont understand why you must use parentheses...unless I show you...

OpenStudy (anonymous):

Whoelse said 3/7....it's -3/7

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=5%283%2Bw%29 The answer is under alternate form

OpenStudy (anonymous):

would it be root???

OpenStudy (anonymous):

root is like this 4X4=16 so roor 16=4

OpenStudy (anonymous):

3X3=9 so root 9 =3

OpenStudy (anonymous):

5X5=25 so root 25=5 and so on

OpenStudy (anonymous):

Oh gosh...the answer is under ALTERNATE FORM!!!!!!!

OpenStudy (bahrom7893):

r-4/7 = -1 add 4/7 to both sides: r - 4/7 + 4/7 = -1+4/7 r = -1+4/7 r = 4/7-1 r = 4/7-7/7 r = -3/7

OpenStudy (anonymous):

Roseanne, I think something is wrong with you....lol

OpenStudy (anonymous):

sorry u mean the root of equation it is mean all the value of the variable satisfy the equation

OpenStudy (anonymous):

dude my bf hates me and hes been on my mind all day im trying lol

OpenStudy (anonymous):

I'm sorry to hear that

OpenStudy (anonymous):

rose take it easy

OpenStudy (bahrom7893):

anybody here good at linear algebra????

OpenStudy (anonymous):

yes

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!