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g(x) = x / (x-2) g'(x) = ?
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Using quotient rule you have: \[f'(x)=\frac{(1)(x-2)-(x)(1)}{(x-2)^2}=\frac{-2}{(x-2)^2}\]
you forgot to put g'(x) instead of f'(x)...now Bovice is confused...
lol
Lol. it should be g'(x)
:-)
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oh yeah totally confused :s lol
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