is this correct? 4x^6+32x^3 4x^3(x^3-8)
yea.. but i believe you can factor x^3-8 further.. look up a^3-b^3 i dont remember the formula off the top of my head.. sorry ..
x^3-8 = x^3-2^3
a^3-b^3 = (a-b)(a^2+ab+b^2)
so: 4x^3(x^3-8) = 4x^3(x-2)(x^2+2x+4)
lol .... i used +- :)
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