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A flashlight has 6 batteries, 2 of which are defective. If 2 are selected at random without replacement, find the probability that both are defective.
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\[\frac{2}{6}\times \frac{1}{5}\]
1/15
i get \[\frac{1}{15}\]
probability both are defective is probability first one is times probability second one is GIVEN that the first one is
\begin{array}l\color{red}{\normalsize\text{r}}\color{orange}{\normalsize\text{i}}\color{#9c9a2e}{\normalsize\text{g}}\color{green}{\normalsize\text{h}}\color{blue}{\normalsize\text{t}}\color{purple}{\normalsize\text{?}}\color{purple}{\normalsize\text{}}\end{array}
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so its 1/15
yea
thanks
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