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A flashlight has 6 batteries, 2 of which are defective. If 2 are selected at random without replacement, find the probability that both are defective.
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\[\frac{2}{6}\times \frac{1}{5}\]
1/15
i get \[\frac{1}{15}\]
probability both are defective is probability first one is times probability second one is GIVEN that the first one is
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so its 1/15
yea
thanks
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