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factor completely 1 - w8
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1 ( 1-w8)
1-(w^4)^2=(1-w^4)(1+w^4)=(1-(w^2)^2)(1+w^4)=(1-w^2)(1+w^2)(1+w^4) =(1-w)(1+w)(1+w^2)(1+w^4)
myininaya these are the choices I have to choose from: a. (1 + w4) (1 + w2) (1 - w2) b. (1 + w4) (1 + w2) (1 + w) (1 - w) c. (1 + w4) (1 - w4) d. not factorable
myininaya these are the choices I have to choose from: a. (1 + w4) (1 + w2) (1 - w2) b. (1 + w4) (1 + w2) (1 + w) (1 - w) c. (1 + w4) (1 - w4) d. not factorable
ok whats wrong?
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you do know multiplication is commutative right? examples: a*b*c=c*a*b=b*a*c and so on.. 3*2=2*3 2*4*3=4*2*3 and so on...
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