Question

what is the quadratic equation for 100-121a^2

Answer 1

The quadratic formula is:
\[x = (-b +- \sqrt{b^2-4ac})/2a\]

and the standard quadratic form is:
ax^2 + bx + c = 0

So we can rewrite your equation as:
-121(a^2) + 100(b) + c = 0

and for the quadratic formula we get:
a = -121
b = 100
c = 0

Simply substitute and solve for X