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solve a2 + 8a + 12 = 0 the solution(s) is/are a = __? or there is no solution
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a = -2 a = -6
\[a^2+8a+12=0\]\[(a+6)[(a+2)=0\] \[(a+6)=0\]\[a=-6\]\[(a+2)=0\]\[a=-2\]
thanks california.mathematics for the arrival to the answer
uwc
so the anser is -6, -2 right
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plug it in and check which one solution
i don't know exactly how to do that
\[-6^2+8(-6)+12=36-48+12=0\] \[-2^2+8(-2)+12=4-16+12=0\] yes:: -6 and -2 is solution
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