Question

show that x^2+ax+y^2+c=0 is the equation of the circle if and only if a^2+b^2-4c>0

Answer 1

wheres b?

Answer 2

sorry x^2+ax+y^2+by+c=0

Answer 3

ok im watching true blood if you want to say something about this you can be i might not come back for another hour

Answer 4

lol okay i'll probably be in bed but thanks myininaya!

Answer 5

you used method of completion of the squares ok i understand lol!! have fun...!

Answer 6

i wanted to say one more thing
r^2>0 because if isn't then you get an imaginary number