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Solve 27-6(x-10)>-3x+26 Write your solution using set builder notation.
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\[x<\frac{61}{3} \]
Start by subtracting 27 from both sides.. \[\implies -6(x-10) \gt -3x -1\]Distribute the -6\[\implies -6x + 60 \gt -3x - 1\]Add 6x to both sides\[\implies 60 \gt 3x -1\]Add 1 to both sides\[\implies 61 \gt 3x\]Divide by 3\[\implies x \lt \frac{61}{3}\] From here we just need to do set builder notation..
Typically for set builder you can just put the inequality you find inside the notation: \[\{x| x \lt \frac{61}{3}\}\]
ok i see thank you very much, now only 10 more to go! lol
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