Question

Solve using calculus
1000ln(1+x/400)+600-1.5x-300

Find the maximum

Answer 1

(266.6677,410.82562)

Answer 2

can u show working

Answer 3

i did it on my calculator. sorry don't have time to explain how to do it.

Answer 4

cmon i can do it on calculator also I need to show working out

Answer 5

sorry my homework is due in couple of hours. and i need to find out how to do it. Right now i don't get it at all.

Answer 6

take derivative and set it equal to 0. solve for x
1+(x/400) = (400+x)/400
d/dx 1000ln((400+x)/400) = 1000/(400+x)
=> 1000/(400+x) - 1.5 =0
1000 = 1.5x +600
400 = 1.5x
266.67 = x
substitute it into original function to find max