Question

4-z 2
--- = --- solve z=
6-z z-6

Answer 1

(4-z)(z-4) = (2)(6-z)

4z - 16 -z^2 +4z = 12 - 2z

-z^2 +8z - 16 = 12 - 2z

-z^2 +10z -28 = 0

z^2 - 10z + 28 = 0

(z-6 ) (z-4) = 0

equating the 2 factors by 0, we have :

z - 6 =0 ; z -4 =0

z = 6 ; z = 4. :]]