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2.) 2abc{abc[abc(abc)^2]^2}^2
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2a^15b^15c^15
In case you can't see where the answer comes from, working from the inside to the outside, start with abc, square and multiply by abc 3 times so the exponent goes to 3, to 7, to 15 (double and add 1), finally multiply by 2 to get the answer given by josephniel14 which I would write as 2(abc)^15.
2(a^15)(b^15)(c^15)
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