Solve 1. y <= 4x-1 2. -2x+3y<-6 3. 5x+3y>-6 and 2y+x<6 4. 2x-3y≥9 and -x-4y≥8 HEEEELP PLEASEEEE !!!!
1. You have a line : y=4x-1 : the solution is this line and the part of the plane above the line (the right part) : you search all the parts of the space which make the ineqality true. it's the same for others.
@Niti Vizato drejtezen 4x-1 dhe pasi ta kesh vizatuar ate gjithe pjesa poshte asaj drejteze+vete dr eshte zgjidhe e inekuacionit....
falemnderit angela shume, domethene vetem vijen duhem ta gjej, a po ?
po ne boshtin koordinativ vizato dr dhe pastaj si ta shpjegova me siper
for problem # 2 you need to divide everything by 3 and the problem will turn into -2/3x9+y<-2, thenext step is to subtract -2/3x on both sides witch now the problem will be y<2/3x-2
ndersa 3 dhe 4 jane sisteme qe zgjidhen njelloj si ato qe te kam shpjeguar disa dite me pare :)
thank you very much !!!
you are welcome
do you have facebook brother ?
yes its lilJohn161651@yahoo.com/facebook.com
with what name are you ?
john thompson or lilJohn161651
i just added you, my name's rinit kadriu
nice to meet you where are you from
go to chat on fb, if u have time man
give me about two hours cause i have a doctors appointment
it;s okay man..
but i will hit you up when i get back
hey rinit u understood?
yes man, thank you very much, whats your name bro, i'll add you in facebook.
himanish
your surname ?
ganjoo..ull get only one hit
i added you, thanks man !
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