abcd is a rectangle. find the length of each diagonal.ac=2(5a+1) bd=2(a+1).

Question

angela210793 · Answer

Is there anything else given

anonymous · Answer

no.

angela210793 · Answer

I'm sorry....nothing's on my mind right now...ask Amistre he/she may know how to solve it

anonymous · Answer

distribute & add/ sub. like terms from there  so:
2(5a+1)=2(a+1) 
10a+5=2a+2
(10a-2a)+5=(2a-2a)+2
8a+5=2
8a+(5-5)=(2-5)
8a=-3
a=-3/8

anonymous · Answer

In a rectangle both diagonal are of equal length.
so 2(5a+1)=2(a+1)
Opening brackets and expanding, we get
10a+2=2a+2
Separating terms with variable on one side, we get
10a-2a = 2-2
8a = 0
a = 0/8 = 0

so ac =  2(5a+1) = 2(5*0 + 1) = 2(1) = 2
     bd = 2(a+1)  = 2(0 +1) = 2(1) = 2

anonymous · Answer

LadiiTreble made a mistake in calculations....

anonymous · Answer

oh i did woops!

anonymous · Answer

it happens to best of us, i hv made my own bloopers many a time.....

anonymous · Answer

Don't worry, be happy :D