Question

Show an equation and a solution for the problem. How much water must be added to 12 L (liters) of a 40% solution of alcohol to obtain a 30% solution?

Answer 1

(0x)+12*.4=(12+x).3
I am not sure

Answer 2

In 12L there is 40%alcohol
hence amount of alcohol=12*40/100 =4.8L

Answer 3

4.8L=30%
hence
4.8= total volume*30/100
total volume=16L

Answer 4

therefore water added=4L

Answer 5

thank you very much for the help I am not great at math you are truley life savers : )