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OpenStudy (anonymous):
Show an equation and a solution for the problem. How much water must be added to 12 L (liters) of a 40% solution of alcohol to obtain a 30% solution?
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OpenStudy (anonymous):
(0x)+12*.4=(12+x).3 I am not sure
OpenStudy (sriram):
In 12L there is 40%alcohol hence amount of alcohol=12*40/100 =4.8L
OpenStudy (sriram):
4.8L=30% hence 4.8= total volume*30/100 total volume=16L
OpenStudy (sriram):
therefore water added=4L
OpenStudy (anonymous):
thank you very much for the help I am not great at math you are truley life savers : )
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