Question

One number is three less than four times another. If their difference is 48, what is the larger number?
a.17
b.51
c.65

Answer 1

Let x = first number
y = second number
x = 4y-3
so for the equation we would be using y and (4y-3)
we assume that 4y-3 is the larger number.

their difference is
(larger) - (smaller) = 48
(4y-3) - (y) = 48
4y - 3 - y = 48
3y = 51
y = 17
4y - 3 = 4(17) - 3 = 68 -3 = 65