Question

I am doing characterstic polynomin and I got -2 (landem) -(landem) square -1.....what would my eigenvectors be?

Answer 1

sorry its landa..my mistake;)

Answer 2

see: http://www.sosmath.com/matrix/eigen2/eigen2.html

Answer 3

solve
\[-\lambda^2-2\lambda -1=0\]
\[\lambda^2+2\lambda +1=0\]
\[(\lambda+1)^2=0\]
so one eigenvalue is
\[\lambda = -1\]

Answer 4

then compute
\[AX=-X\] or
\[AX+X=0\]
to get eigenvectors.