hey are some trig or alg 3 topics talked about in here
simply problems are solvd here
alg 3 or trig probs?
yes
what are the problems?
ok what do you do if the directions say solve the quadratic inequality (x^2-4x+3 is greater than or equal to 0
well, you can factor this quadratica and then solve for the zeros
Then make a table and determine in what regions or region the inequality is true
which way do the inequalities point
Well, i would have to solve your problem first o know that , so let me doit
x< or>3 and 1
?
The answer is going to be \[(-\infty,1]\cup[3,\infty)\]
I used to be a wiz at math but I was run over by a truck and had a traumatic brain injury
lagrangeson has it. you do not need a table however. all you need to remember is that \[y=x^2-4x+3\] is a parabola that faces up. therefore it will be positive outside the zeros and negative between them
The table makes it clear for me :)
but that is not one of my choices?I have 1<x<3
what r ur choices
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