Question

let y=4x^2.
Find the change in y, Δy when x=2 and Δx=0.1
Find the differential dy when x=2 and dx=0.1

Answer 1

8xdx=dy
x=2 you get 16(0.1)=1.6

Answer 2

first one: if x = 2 then y = 16 and if x = 2.1 then y = 17.64 so
\[\delta y =17.64-16=1.64\] yes?

Answer 3

bnut has second one

Answer 4

oh, I see what I was doing. Thanks guys