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Mathematics 17 Online
OpenStudy (anonymous):

can you guys help me evaluate this integral? ∫_0^(∛π)〖x^2 cos⁡(x^3 ) dx〗

OpenStudy (anonymous):

u= x^3

OpenStudy (anonymous):

so integral 0 to pi of (1/3) cos(u) du

OpenStudy (anonymous):

=0

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