Question

find the number of real solutions for the equlation 3x^2+6x+3=0

Answer 1

\[\Delta=6^{2}-4\times3\times3=0\] so there is only one solution

Answer 2

\[3x^2+6x+3=0\]
\[3(x^2+2x+1)=0\]
\[3(x+1)^2=0\]
\[x=-1\]