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indentify the vertex and the axis of symmery for the graph of y=3(x-3)^2+4
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= 3 (x^2 -6x +9) + 4 = 3x^2 - 18x + 27 + 4 = 3x^2 - 18x + 31 vertex = 18 / 6 = 3 axis of symmetry is x=3
axis of symmetry is x = 3, the vertex is (3,4)
yes sorry i didnt give the y cood of the vertex which is vertex = (3,4)
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