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Find the measure of the following numbered angles in circle P when arc AE = 53°, arc BA= 68°, and arc CB = 72°. find angle 3 =
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good luck with that
Is P the center?
angle CDB=36 angle CBD=90-36=54 (angle 8=90degree) arc CDE=360-(53+68+72)=167 ANGLE CBE=167/2=83.5 angle CBE - angleCBD = angle3 ==>> 83.5-54=29.5
If it is then AE + BA subtends 121 atx centre and PBE is isoc so 180-121 over 2 = 29.5
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arc BD = 180 68 + 53 + arc ED = 180 arc ED = 59 m3 = 1/2 * 59 m3 = 29.5
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