Question

HELP!:

factor: -4x3 - 19x2 - 15x - 12

Answer 1

-4x^3-19^2-15x-12
well, i guess you could put parantheses to seperate the terms

Answer 2

easiest way is use synthetic division to factor out a binomial (x +- c) where c is a factor of 12
if remainder is 0 then it factors
try x+1:
-1| -4 -19 -15 -12
_______4_____15___0____
-4 -15 0 -12
Does Not work
try x+2
-2| -4 -19 -15 -12
_______8_____22___-14____
-4 -11 7 -26
Does Not work

try x+3
-3| -4 -19 -15 -12
________12___21___-18____
-4 -7 6 -30
Does Not work
try x+4
-4| -4 -19 -15 -12
________16___12___12____
-4 -3 -3 0
Works

=> (x+4)(-4x^2 -3x -3)

Answer 3

Well :D looks like someone got it for you, good job man!