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OpenStudy (anonymous):
The graph of y = ax^2 + bx + c is a parabola that opens up and has a vertex at (0, 5). What is the solution set of the related equation 0 = ax^2 + bx + c?
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OpenStudy (anonymous):
x^2+5
OpenStudy (dumbcow):
so using that equation, x^2 +5 = 0 solve for x to obtain solution x = +-sqrt(5)i
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