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Mathematics 9 Online
OpenStudy (anonymous):

The graph of y = ax^2 + bx + c is a parabola that opens up and has a vertex at (0, 5). What is the solution set of the related equation 0 = ax^2 + bx + c?

OpenStudy (anonymous):

x^2+5

OpenStudy (dumbcow):

so using that equation, x^2 +5 = 0 solve for x to obtain solution x = +-sqrt(5)i

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