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Which of the following equations has only one solution? x2 - 8x + 16 = 0 x(x - 1) = 8 x2 = 16
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the first one has one solution of multiplicity 2
A,B,or C?
i do not see A,B, or C i did say first one though
A.x2 - 8x + 16 = 0 B.x(x - 1) = 8 C.x2 = 16
A. has one solution
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because b*(2) - 4ac = 0 and hence x_1,_2 = (8+/_ 0)/2 = 4
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